Lauren H. answered 08/17/18
Tutor
4.8
(24)
7 years experience teaching High School Chemistry and Honors Chemistry
Fang:
Write the balanced equation:
CaCO3 + HCl → CaCl2 + H2CO3 → CaCl2 + H2O + CO2 ( carbonic acid forms CO2 and H2O immediately)
CaCO3 + HCl → CaCl2 + H2O + CO2
Balance:
CaCO3 + 2HCl → CaCl2 + H2O + CO2
Now you have a balanced equation so that you can find the proper mole ratio.
Begin with the given:
16.93 g of CaCO3 x 1 mole CaCO3/100.09 g CaCO3 x 1 mole CO2/1 mole CaCO3 x 44.01g CO2/1 mole CO2 = 7.44 g CO2
This is the theoretical yield.
Actual Yield = Theoretical yield x % Yield
AY = 7.44 g CO2 x .516 = 3.84 g CO2