The sum of three numbers is 140. The third number is 4 times the second. The second number is 10 more than the first. What are the numbers?

Question

The sum of three numbers is 140. The third number is 4 times the second. The second number is 10 more than the first. What are the numbers?

Answer 1

So let's call the first number X

Then,

the 2nd number is X + 10

the 3rd number is is 4 times the second number = 4(X + 10) = 4X + 40

So now we know the sum of the three numbers is 140:

X + (X + 10) + (4X + 40) = 140

6X + 50 = 140

6X = 90

X = 15

 

So, the numbers are:

 

15, 25, 100

 

Let's check our answer:

15 + 25 + 100 = 140