Iskandar K.

asked • 07/20/18

Given the value of x²-x-3 = a(x-1)²+b(x-1)+c. Determine the value of a,b and c

If i want to find a, do i need to move  a(x-1)² to LHS and start from there?

1 Expert Answer

By:

Andy C. answered • 07/20/18

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Iskandar K.

I will open my textbook again.
 
I understand the answer till this part  = ax^2 + (b-2a)x + (a-b+c) <--- CLT
 
I will read more on Equating Coefficients chapter.
 
Thnak you so much 
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07/20/18

Andy C.

CLT stands for COMBINE LIKE TERMS....
the coefficients of x and  B and -2A 
a  , -b, and C are the remaining constants
so all that step does is combine them into a single term
just as you would combining like terms
 
 
Next the two polynomials on the left and right are the same, so their
coefficients must be the same.
 
Therefore,  A, the coefficient of x^2 on the right MUST be the same as 1,
the coefficient of x^2 on the left.
 
LIkewise, b-2a, the coefficient of x on teh right MUST be the same as -1,
the coefficient of x on the left
 
Finally, the constant term on the right a-b+c MUST be the same as the constant term on the left
which is -3.
 
Equating these coefficients results in the three equations listed.
Solving this 3x3 system of equations results in a=b=1 and c=-3
 
Plugging them into the polynomial on the right and simplifying
gives the polynomial on the left which proves the answer is correct
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07/20/18

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