HELP ME PLEASE

Question

Find three odd consecutive integers such that the sum of the squares of the first and second integers is equal to the square of the third integer minus 7.

Answer 1

a² + (a + 2)² = (a + 4)² - 7

a² + a² + 4a + 4 = a² + 8a + 16 - 7

a² - 4a - 5 = 0

(a - 5)(a + 1) = 0

 

a - 5 = 0

a = 5

5,7,9

 

a + 1 = 0

a = -1

-1,1,3