Herb K. answered 07/20/18
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semi-retired college professor (math/physics), patient, non-judgmental
y(x) = a(x - 2)(x + 4) = a(x^2 + 2x - 8) = a[(x^2 + 2x + 1) - 1] - 8a; then: y(x) = a(x + 1)^2 - 9a; choose a = -1
then: y(x) = -(x + 1)^2 + 9
Mark M.
07/20/18