The zeroes of f(x) = x2 – 8x + 17 are?

Question

The zeroes of f(x) = x2 – 8x + 17 are?

Answer 1

The discriminant is:

 

b² - 4ac = (-8)² - 4(1)(17) = 64 - 68 = -4

 

When the discriminant is less than zero, f(x) has no zeros in the real number set.