Benjamin P. answered 07/01/18
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Here is an easy way to understand the problem and to do the calculations. This a simultaneous equations problem. You are given both of them when you are told that there are six thousand seats of two kinds, which may be called X and Y; that the prices of the tickets are $25 and $40; and that the revenue must add up to $174,000.
The number of X and Y seats is 6,000.
So X + Y = 6,000
The number of dollars can then be matched up to form the other equation by finding all the facts with a dollar sign.
So, there are X seat at $25 each and Y seats at $40 each totaling $174,000. "At" means multiply.
This is the same thing as saying 25X + 40Y = 174,000.
But we don't like two variables. It would be nice for one of them to subtract out before we go any further.
So if we take our easier equation and multiply all of its terms by the smallest number in the other equation, we get:
(25)X + (25)Y = (25) 6,000
Which simplifies to: 25X + 25Y = 150,000
Now put the equations together and subtract to get rid of one of the variables:
25X + 40Y = 174,000
25X + 25Y = 150,000
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15Y = 24,000 Divide each side by 15 to get
Y = 1,600
Now 25X + 40 (1,600) = 174,000 Which simplifies to:
25X + 64,000 = 174,000 Subtract 64,000 from both sides to get:
25X = 110,000 Divide each side by 25 to get:
X = 4,400
To summarize, 1,600 $40 tickets plus 4,400 $25 tickets gets you $174,000.