I consider we are looking for the line that contains points (2, 6) and (-3,5). There is exactly one line.
We can use point slope formula and transform the equation to have the form desired.
We find slope first.
slope = (y2-y1)/(x2-x1)
slope = (6-5)/(2-(-3))
slope = 1/5.
Next, we use the point slope formula.
y-y1=slope(x-x1).
y-6=1/5(x-2),
y-6=1/5x-2/5.
We change this equation using equivalent transformations to obtain the desired form.
1/5x-y =6 2/5.
We can get rid of fractions by multiplying this equation by 5.
x - 5y = 32.
a=1, b=-5, c=32.