Nihar H.

asked • 06/25/18

If a^2 + b^2 = 11ab and a>b >0, prove that {(a-b)/3}=1/2 (log a + log b)

If a^2 + b^2 = 11ab and a>b >0, prove that {(a-b)/3}=1/2 (log a + log b)

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