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Harry B.

asked • 06/13/18

The roots of x^3+6x^2+4x+2=0 are r, s, and t. For what order triple of integers (a,b,c) are 2r, 2s, and 2t the roots of x^3+ax^2+bx+c=0?

roots of x^3+6x^2+4x+2=0 doubled equals the coefficients in x^3+ax^2+bx+c=0

1 Expert Answer


Andy C. answered • 06/13/18

4.9 (27)

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