Solve for n in: 16^n = cube√(2^2)

Question

I'm giving an equation in that form and ask to solve for n...  How do I solve for n? 

Answer 1

16ⁿ = (2²)^1/3

 

16ⁿ = (4)^1/3

 

n log₄16 = (1/3) log₄4

 

n(2) = (1/3)(1)

 

n = 1/6

 

Test the answer.