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Fruit F.

asked • 05/24/18

Find angle ACB in terms of x using tangent

Angle ABC = x
Line BC is tangent to circle centre O
Line AOC is a straight line
Find angle ACB in terms of x

I got 270-2x:
Angle OAB = OBA = x-90
Angle ACB= 180-(x-90)-x
Apperently this is the wrong answer but I can't wrap my head around why.

Thanks

![enter image description here](https://i.stack.imgur.com/gt0CF.png)
 

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