I think these questions are supposed to be answered using the binomial distribution function. I will give you some suggestions, but I will not solve the problem for you entirely.
The probability of outstanding is 10%; that means probability of "not outstanding" is 90%. The answer to "A" then is the third term in the binomial density with p=.1 and q=.9.
Two or more outstanding means 0 or 1 not outstanding. For "B" You need the last 2 terms in the same binomial density as in "A" and you subtract the sum of those 2 terms from 1.
For "C" your binomial changes: p=.85 and q=.15. Her you want the sum of the 1st two terms subtracted from 1
For "D" your binomial p=.05 and q=.95 and you want only the first term.