Andy C. answered 05/02/18
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Math/Physics Tutor
f(a+1) = 2(a+1)^2 - 5(a+1) = (a+1) {2(a+1) - 5} = (a+1) { 2a - 3} = 2a^2 - a - 3 = ( 2a - 3)(a + 1 )
f(1) = 2*1^2 - 5(1) = 2*1 - 5(1) = 2-5 = -3
f(a+1)-f(1) = (a+1)(2a-3) - (-3)
= (a+1)(2a-3)+3
= 2a^2 - a - 3 + 3
= 2a^2 - a
= a(2a-1)