square root of 8 over the square root of 3+1

Question

√8

—

√3+1

 

 

Answer 1

Multiply numerator and denominator by 

 

√3 - 1   

 

and note that

 

(√3 + 1)(√3 - 1) = 3 - 1 = 2

 

The denominator becomes 2 and you are left with

 

(√3 - 1)√8 / 2 = (√3 - 1) (2√2) / 2 = √6 - √2