Y varies directly as x^2 and inversely as z. If y=12 when x=2 and z=7, find y when x=3 and z=9?

Question

^{What will the answer be and please break it down in steps so I can understand were you got the answer from.}

Answer 1

y = kx²  direct variation

yz = k   inverse variation

 

yz = kx²

(12)(7) = k(2²)

21 = k

 

y(9) = 21(3²)

 

Can you solve for y and answer?