Verify the following Identity:

Question

tanθcos2θ=(2tanθcos2θ-tanθ/1-tan2θ)

Bobosharif S. · Accepted Answer

Is think it should be + instead of -in (2tanθcos2θ-tanθ/1+tan2θ). Then
(2tanθcos2θ-tanθ/1+tan2θ)=
=tanθ(2cos2θ-1/(1+sin2θ/cos2θ) = tanθ(2cos2θ-cos2θ) =tanθcos2θ.

Verify the following Identity:

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Verify the following Identity:

1 Expert Answer

Still looking for help? Get the right answer, fast.

OR

RELATED TOPICS

RELATED QUESTIONS

Help with Trig Equations

show that cos(A-B) - cos(A+B) = 2sinA sinB

(TanX)-1)/(Tan(X)+1) = (1-cot(X))/(1+cot(X))

1/1-cosx+1/1+cosx=2csc^2x

secx-tanxsinx=1/secx

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