Pretty algebra Word Problem

Question

find three consecutive odd intergers such that five times the smallest is the same as the result when twice the sum of the other two is decreased by 109

Answer 1

5s = 2(m+L) - 109

s= x, m=x+2, L = x+4

5x = 2(x+4 + x+2) -109

5x = 4x -97

x = -97

s, m, L = -97, -95, -93 = the 3 consecutive odd integers

5(-97) = - 485

2(-95-93) -109 = 2(-188) -109 =-376 -109 = - 485