Christopher has three times the number of ds games as he does wii games. each ds game costs $30 each wii game costs $50. how many of each type of game?

Question

He spent $700 total.

Answer 1

Samantha,

 

Lets call the number of ds games D, and the number of wii games W.  Now Christopher has 3 times as many ds games as he does wii games so:  D = 3W.

 

Also he spent $700 on D games @ $30 each and W games @ $50 each so:

 

30D + 50W = 700.

 

Since D = 3W we can replace D above and write:

 

30(3W) + 50(W) = 700 ⇒ 90W + 50W = 700 ⇒ 140W = 700, so W = 700/140 = 5

 

If he has 5 wii games, then he has 3x5 = 15 ds games:

 

Check:

 

$30 x 15 = $450

$50 x 5   = $250

$450 + $250 = $700

Answer 2

x = number of wi games

cost of wi games = $50(x)

3x = number of ds games

cost of ds games 30(3x)

 

30(3x) + 50(x) = 700

90x + 50 x = 700

140x = 700

x = 5 wi games

3x = 15 ds games