Arthur D. answered 03/23/18
Tutor
4.9
(306)
Forty Year Educator: Classroom, Summer School, Substitute, Tutor
3x+y=10
4x-z=7
7y+2z=17
from eq1, y=10-3x
from eq2, z=4x-7
substitute into eq3
7(10-3x)+2(4x-7)=17
70-21x+8x-14=17
56-13x=17
56-17=13x
39=13x
x=39/13
x=3
3x+y=10, 9+y=10, y=1
4x-z=7, 12-z=7, z=5
x=3, y=1, z=5