two sets of three consecutive intergers have a property that the product of the larger two is one less than seven times the smallest

Question

the answer to this question must be set up as an equation 

Answer 1

The 3 consecutive integers are

 

n (smallest)

n + 1

n + 2 (largest)

 

The wording of the question translates into

 

(n + 1)(n + 2) = 7n - 1

 

Solve for n.

 

n² - 4n + 3 = 0

 

(n - 3)(n - 1) = 0

 

n = 3 or 1, which gives 2 sets:

 

3,4,5 and 1,2,3

 

Test the answers.