Raymond B. answered 12/13/20
Math, microeconomics or criminal justice
At price =7, quantity purchased = (-9/4)(7)+19 = --64/4 + 19 = 76/4 - 64/4 = 12/4 = 3
x'(p) = (-9/4), for an increase in p, x decreases. It's an inverse relation
p goes up 1 and x goes down 9/4 = 2.5 elasticity = .5/3 all over 1/7 = 5/30 x 7 = -7/6 = -1.67 which is elastic, less than 100%
price elasticity of demand = % change in x divided by % change in p
as p changes from 7 to 14, a 100% increase in price, x changes from 3 to 0, a 100% decrease. -50/100 =-1/2 >-1, which is inelastic,
take the x(p) equation, x=-(9/4)p +19, and solve for p=(4)(19)/9 -4x/9 = 76/9 -(4/9)x
multiply p by x = revenue = xp= (76/9)x-(4/9)x^2
take the derivative and set equal to zero, solve for x
R' = (px)' = 8 4/9 - (8/9)x = 0
x = (9/8)(76/9)= 9.5
when x=9.5, p = (4/9)(19) - 4(9.5)/9 = 4 2/9 = 4.222...
that point is the point elasticity of 1 (or -1, the negative sign is assumed) = unit elasticity
p= 4.222... with x = 9.5.
p<4.222... is elastic
p>4.222 ... is inelastic
p=4.222.... is unitary elasticity
7 > 4.222... so at that point, the demand curve is inelastic
4.222... is the midpoint between maximum price & zero
where quantity demanded is the midpoint between 19 and zero.