find all solutions x^3+49x=0
Factoring, you get x (x^{2} + 49) = 0
so x = 0 or x^{2} + 49 = 0 ==> x^{2} = -49
If only in the real number system, then x = 0 is the only solution.
If Complex numbers, then x = 0, x = +7i, x = -7i
find all solutions x^3+49x=0
Factoring, you get x (x^{2} + 49) = 0
so x = 0 or x^{2} + 49 = 0 ==> x^{2} = -49
If only in the real number system, then x = 0 is the only solution.
If Complex numbers, then x = 0, x = +7i, x = -7i