the "e" in this equation deals with logarithms. I understand that you change the ''e'' to ln which means natural log but then I don't know what to do next.

Sometimes a change of variables makes the problem easier. In this instance, we can let y = e^{x}

Then we have y - 30/y = 1 or after multiplying by y, and moving everything to the left side,

y^{2} - y - 30 = 0

(y + 5)(y - 6) = 0

y = -5 or 6

Now the only real solution is x = ln 6.

x = ln -5 is a complex number as you will learn in more advanced math classes. ln fact ln -5 = ln 5 + πi.

## Comments

Good answer, Kevin.