
Rafael F.
asked 02/12/18Find the value of log(a,(b)) it uses.
log base(ab) [2log base(ab)(√a)-1/2log base(ab)√ab(b)]=(log base(ab) (a))^2-(log base(ab)(b))^2
I do not know
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1 Expert Answer

Bobosharif S. answered 02/12/18
Tutor
4.4
(32)
PhD in Math, MS's in Calulus
LHS:
logab[logab(a)-logab( (ab)1/4√b)]=logab[logab(a(ab)-1/4b-1/2)]
logab[logab(a)-logab( (ab)1/4√b)]=logab[logab(a(ab)-1/4b-1/2)]
In the RHS:
(logab(a))2-(logab(b))2=(logab(a))-(logab(b))((logab(a))+logab(b))=
=logab(ab)*logab(a/b)=logab(a/b), since logab(ab)=1
So we have
logab[logab(a(ab)-1/4b-1/2)]=logab(a/b).
We can write as
logab[a(ab)-1/4b-1/2)]=a/b =logab[(ab)(a/b))]
a(ab)-1/4b-1/2=ab(a/b)
Next...
The question doesn't have a precise statement.
We can write as:
logab(a/b)=(4/3)(a/b)
But again it is not clear what we are looking for.
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Bobosharif S.
02/12/18