
Arturo O. answered 02/02/18
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Student,
For the problem as worded, David W. gave you the correct answer. But perhaps you really meant to ask:
"What is the simplest polynomial WITH REAL COEFFICIENTS that one can get from the zeros 8i, 3, and -3?"
If that is the real question, then you need to recall that if you have a complex zero, its complex conjugate is also a zero. The simplest polynomial will have the lowest possible degree for the set of zeroes, and a leading coefficient of 1. The zeros are
8i
-8i
3
-3
The degree is 4. The simplest polynomial is the expansion of
p(x) = (x - 8i) [x - (-8i)] (x - 3) [x - (-3)] = (x2 + 64)(x2 - 9) = ?
You can expand this further if you wish.