solving an equation with postive rational exponent

Question

Solve (y-6)^4/3=4 where y is a real number.
Simplify your answer as much as possible.
(If there is more than one solution, separate them with commas.)

Answer 1

(y-6)^4 = 12

(y-6)^2 = + or - sqr12 = + or - 2sqr3

y-6 = sqr(2sqr3) or -sqr(2sqr3) or some imaginary solutions, sqr(-2sqr3) or sqr(-2sqr3) or -sqr(-2sqr3)

y = 6 plus any of those 4 solutions, 2 real, 2 imaginary

y = 6+sqr(2sqr3), 6-sqr(2sqr3), 6+isqr(2sqr3), 6-isqr(2sqr3)

y = about 11.2, 4.1, 6+1,8i, 6- 1.8i