
Al P. answered 01/31/18
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S(t) = 2000t / (4+0.1t); t=0 at year 2005
You need rate of change, that implies taking a derivative:
Let's write S(t) as this: S(t) = 20000 * (t/(40+t))
Using the quotient rule:
S'(t) = 20000 * (40 / (40+t)2)
S'(t) = 800000/(40+t)2
2009 is represented by t=4, so just plug in t=4 into S'(t)
S'(4) = 800000 / (40+4)2 = _________________ thousands of dollars per year
If needed, multiply the answer you get by 1000 to get dollars per year.