David W. answered 01/28/18
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Experienced Prof
Let x = number of TF questions (4 points each)
y = number of MC questions (8 points each)
Here is some very important information:
(points per question)*(number of questions) = points [because questions cancel out]
"test has twenty questions" means x+y=20 [eq1]
"100 points" means
(number of points for TF questions) + (number of points for MC questions) = 100
4x + 8y =100 [eq2]
Substitution Method:
Solve for a variable usinf [eq1]: x=20-y
Substitute for x in [eq2]:
4(20-y) + 8y = 100
80 - 4y + 8y = 100
80 + 4y = 100
4y = 20
y = 5
There are 5 multiple-choice questions.
Use either [eq1] oe [eq2] to find the value of x:
x + y = 20
x + 5 = 20
x = 15
There are 15 True-False questions.
Check: Is 4(15) + 8(5) = 100 ?
60 + 40 = 100 ?
100 = 100 ?yes
David W.
In the second line of that group of calculatiobs, (-4y+8y) became 4y to produce the third line. The fourth line of that group is the result of subtractibg 80 from each side of the third line, so we are get 4y = 20.
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11/16/22
Sadie G.
David D, where did the 8y go in the "substitute for x using [eq2] go? And where did the 80 go?11/16/22