x+3y=4

2x+3y=2

x+3y=4

2x+3y=2

Tutors, please sign in to answer this question.

Gainesville, FL

You would take one equation and subtract it from the other like this:

2x + 3y = 2

- x + 3y = 4

______________

x + 0 = -2

So we found that x = -2. We can then plug in -2 into x for either one of the equations and solve for y:

(-2) + 3y = 4

3y = 6

y = 2

Although, you have, as your topic, "Solving Systems By *Substitution*", so to do substitution, you would first solve one of your equations for one of the variables (let's say, the second equation, and that we will solve for x).

Taking the second equation and solving for x, we get:

x = 4 - 3y

You can then plug in what you have just found as x into the other equation like this:

2x + 3y = 2

2(4 - 3y) + 3y = 2

Solving the equation for y, we get:

2(4 - 3y) + 3y = 2

8 - 6y + 3y = 2

8 - 3y = 2

-3y = -6

y = 2

And then you can plug in this value for y into any one of the first equations to solve for x.

Saugus, MA

x+3y=4

2x+3y=2

by substitution...

x+3y=4, x=4-3y

2x+3y=2

2(4-3y)+3y=2

8-6y+3y=2

8-3y=2

-3y=2-8

-3y=-6

y=2

x+3y=4

x+3(2)=4

x+6=4

x=4-6

x=-2

(-2,2) is the solution

Starlyte H.

Ivy League Tutor

Bronx, NY

5.0
(181 ratings)

Adam P.

Highly Experienced Test Prep Instructor

Brooklyn, NY

4.9
(85 ratings)

Jessica L.

International Baccalaureate graduate available for short notice

Jamaica, NY

5.0
(10 ratings)

- System Of Equations 317
- Substitution Method 124
- Math Help 4691
- Word Problem 4529
- Algebra 1 3586
- Word Problems 1278
- Word Problem Help 1001
- Equations 624
- Algebra 1 Word Problem 324
- Equation Word Problem 146