Find the solution tothe system of linear equations by substitution for the following, 5x+2y=10 and 3x+4y=6

Question

Enter the system's solution as an ordered pair including the comma. If the system has no solution enter "none". If it has infinitely many solutions, enter "infinitely many solutions."

Answer 1

5x+2y=10

3x+4y=6

3x=6-4y

x=2-(4/3)y

5(2-(4/3)y)+2y=10

10-(20/3)y+2y=10

-(20/3)y+2y=0

you don't have to continue here because y can only be 0

5x+2(0)=10

5x+0=10

5x=10

x=2

(2,0)