Kenneth S. answered • 01/22/18

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Expert Help in Algebra/Trig/(Pre)calculus to Guarantee Success in 2018

part 1: z = r(cos θ + i sinθ)

z

^{2}= r^{2}(cos^{2}θ+ 2isinθcosθ - sin^{2}θ^{) }= r^{2}[cos^{2}θ - sin^{2}θ) + i (2sinθcosθ)] = r^{2}[cos(2θ) + i sin(2θ)].Is this sufficient help?

Kenneth S.

I can see that if theta is in (0,pi) and arg (z

^{2}) = 2θ then 2θ > pi/2 means θ > pi/4.That's about it for me.

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01/22/18

Abhimanyu B.

01/22/18