x^2 - 2x + 9 = 0...find the discriminant & determine types of solutions?

Question

x² - 2x + 9 = 0

 

A.)Find discriminant & determine types of solutions

B.)Solve with with quadratic formula

Answer 1

x² - 2x + 9 = 0

a=1, b=-2, c=9.

D=b²-4ac=(-2)²-4*9=4(1-9)=4*(-8)=-32<=0

Equation has no real roots. 

There are two complex roots: x₁=1- i2 √, x₂=1+i2√ 2, which are conjugate to each other.