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Nick A.

asked • 01/15/18

Discrete math-Mathematical induction

Hello there,
I was just wondering my lecturer deduct my marks for this and gave 1/2 out of 2:
Given 4+8+12+...+4n = 2n^2+2n for n>=1,
My solution: 1. Inductive base: n =1, 4 = 4;
2. Hypothesis: Assume n=k, for k>=1;
3. Step:  n = k+1
4+8+12+...+4k+4(k+1)   =       2(k+1)^2 + 2(k+1)
2k^2+2k+4k+4               =        2(k+1)^2 + 2(k+1)
2k^2+4k+2+2k+2           =        2(k+1)^2 + 2(k+1)
2(k+1)^2 + 2(k+1)          =        2(k+1)^2 + 2(k+1), Hence n = k+1 is true.
 
Is there something wrong with this? 
Lecturer told me that I have to follow his style of writing and did not even consider of me doing this way telling me it is wrong.
Can someone tell me what is wrong?
 
 

1 Expert Answer

By:

Nick A.

Thank you for your answer. My question is my solution wrong?
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01/16/18

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