what is y-y1=m(x-x1) when y1=6 and x1=-1 and m=-5/3

Question

what is y-y1=m(x-x1)

y1=6

x1=-1

m=-5/3

Answer 1

The point-slope form of the equation of a line:

     y-y₁ = m(x-x₁)      where m=slope and (x₁,y₁) is a point

     y-6 = (-5/3)(x-(-1))

     y-6 = (-5/3)(x+1)

 

To get the slope-intercept form of the equation of that line:

    y = (-5/3)x - 5/3 + 6

    y = (-5/3)x + 13/3

Answer 2

Simply place the values into the formula.

 

y-6=(-5/3)(x-(-1))

 

simplify to:

 

y-6=(-5/3)(x+1)