Mark O. answered 12/14/17
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Hi Mariel,
Let's call the points (x1, y1) = (-3, 3) and (x2, y2) = (1, 2).
You want to write a linear formula of the form
y = mx + b
where m is the slope of the line and b is the y-intercept.
The slope = Δy / Δx = (y2 - y1)/(x2 - x1) = (2 - 3) / (1 - (-3)) = -1/4
The equation is now
y = (-1/4)x + b
We now solve for b.
b = y + (1/4)x
We can now insert for (x, y) either (x1, y1) or (x2, y2). I choose (x1, y1) = (-3, 3).
b = 3 + (1/4)(-3) = 12/4 - 3/4 = 9/4
This, the slope-intercept form of the equation that contains the two points given is
y = (-1/4)x + 9/4