How do you solve (y-2)^3?

Question

When I do the first step, I get (-y^2-4y+4)(y-2). I just do not understand how to foil that.

Answer 1

Actually, it is

 

(y^2 - 4y + 4)(y - 2) =

 

  (y^2 - 4y + 4)* y  -  (y^2 - 4y + 4)*2

 

 

 = y^3 - 4y^2 + 4y  - 2y^2 + 8y - 8

 

= y^3 - 6y^2 + 12y - 8