Express the quadratic function in standard form

Question

find max value

f(x)=-(x-3)^2+16

 

Can you also give vertex and x and y intercepts please?

Answer 1

y - 16 = -(x-3)²  In this form, the coordinates (h,k) of the vertex are easily identified as (3,16).

In the form that you began with, the y-intercept is seen to be 16 - (0-3)² which is 7.

You can find the x intercepts by setting y = 0 and solving for x.

The maximum value is at the vertex.