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x + 2y = 3

x + 2y = 3
3y - x = 2
 
 
find dy
 
      b2
 
      b1
 
      c2
      c1

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Mark W. | Math Tutor: Pre-K to Algebra 2Math Tutor: Pre-K to Algebra 2
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I don't really understand you questions, is it find y?
 
x + 2y =3
-x +3y = 2            (you can switch the x and y positions)
5y = 5                  (I added knowing x is different sign same coefficient they cancel)
y = 1                    (divided 5 on both sides)
 
Find x by substituting in either equation.
 
x + 2*1 = 3        (substituting y =1 in the first equation)
x = 1                  (subtracted 2 on both sides)
 
 
Answer (1,1)