Anthony B. answered 08/03/14
Tutor
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Math, Stats, Calculus, APA Tutor, Statistics Consulting
Hello Anne,
First of all, when it comes to statistic, the letters I am using may be different from what your class is using, but the formulas will be the same.
Sine we are dealing with a comparison of proportions between a population and sample, , we need to do a z-test using the formula:
z=(p-π)/σ
π(pi) = population proportion or probability (.5)
p = sample proportion of probability (218/500=.436)
σ = standard deviation
The formula to find standard deviation is:
σ = √(π(π-1)/n)
= √(.5(1-.5)/500
= √(.25/500)
= .02236
We take this back to our z formula.
z = (p-π)/σ
= (.436-.5)/.02236
= (-.064/.02236)
= -2.862
The level of confidence we are given is α=.01. We will use a two tailed test since no direction of difference was expected, meaning .005 in either tail. By looking at your z distribution, you can see that this corresponds to a z score of ±2.58.
Our calculated z of -2.862 is more extreme than the critical z of ±2.58, we reject the null hypothesis. The conclusion is that the proportion is a value other than 50%.
Anthony