
Chris M. answered 11/28/17
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x3+5x2-x-5=0
x2(x+5)-1(x+5)=0
(x+5)(x2-1)=0
(x+5)(x-1)(x+1)=0
Setting each of these factors = 0 and then solving for x yields
x=-5,1,-1
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Cheers
-Chris