Michael J. answered • 11/18/17

Tutor

5
(5)
Best Afterschool Tutor to Prepare You For Your Regents

Complex roots come in conjugates. Your roots are

x = -3i

x= 3i

x = 2

x = -i

x = i

Since i=√-1 , then i

^{2}=-1For the root x = 3i , we can say that the factor is

(x - 3i)(x + 3i) = x

^{2}- 9i^{2} = x

^{2}- 9(-1) = x

^{2}+ 9(x - i)(x + i) = x

^{2}- i^{2} = x

^{2}+ 1Then your polynomial is

**f(x) = (x - 2)(x**

^{2}+ 1)(x^{2}+ 9)