
Andy C. answered 11/07/17
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(A) ------------>
given: lim(Xn)=0
prove: lim(1/Xn) = infinity
lim (1/Xn) = lim 1 / lim (Xn)
= 1 / limXn
Since lim Xn=0, 1/ lim Xn is infinity
Therefore lim 1/Xn^2 = lim (1/Xn)^2 is also infinity
<-------------------
given : lim 1 / (Xn^2) = infinity
prove: lim Xn=0
By contradiction, suppose lim Xn <= k < infinity is bounded above.
lim 1/Xn <= 1/k < infinity
lim 1/Xn * 1/Xn <= 1/k * 1/k = 1/k^2 < infinity
lim 1/Xn^2 <= 1/k^2 < infinity, which is a contradiction
(b) 1/e^n tends to zero
But the reciprocal blows up