DUE AT MIDNIGHT PLEASE HELP. THANK YOU

Question

Given that f(x) is a cubic function with zeros at -5 and -3 i - 2 , find an equation for f(x) given that f(3) = -1.

Answer 1

Since complex conjugates come in pairs, the third zero would be 3i - 2.

x = -5, x = -3i - 2, and x = 3i - 2

x + 5 = 0, x + 3i + 2 = 0, x - 3i + 2 = 0

(x+5)(x+3i+2)(x-3i+2) = (x+5)(x²+3ix+2x-3ix-9i²+6i+2x-6i+4) =

(x+5)(x²+4x-13) = 

x³ + 9x² + 33x + 65 = f(x)