Don L. answered 11/03/17
Tutor
5
(18)
Fifteen years teaching and tutoring basic math skills and algebra
Hi Muilan, the way to solve this type of problem is to set up a table with the information.
Let x represent the amount of high-quality beans.
Bean type Amount Cost Total
---------------------------------------------------------------
High-Quality x 6.00 6.00 * x
Cheaper 130 - x 3.25 3.25 * (130 - x)
Tasti-Delight 130 4.73 4.73 * 130
Equation to solve:
6.00 * x + 3.25 * (130 - x) = 4.73 * 130
Combine terms:
6.00 * x - 3.25 * x = 4.73 * 130 - 3.25 * 130
2.75x = 192.4
x = 69.96, or to the nearest pound, 70.
Shara needs 70 pounds of high-quality coffee beans.
Shara needs 130 - 70, or 60 pounds of cheaper beans.
Check:
6.00 * 70 + 3.25 * (130 - 70) = 4.73 * 130
420 + 195 = 614.9
615 ≈ 614.9
Values check.
Questions?