Kris V. answered 10/25/17
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Let x be the dimension of the shorter side, and y be be the dimension of the longer side of the field.
There are 4 fences along the shorter side, and 2 fences along the longer side, so
4x + 2y = 800 ⇒ y = 400 − 2x
The area of the rectangular field is
A = xy
= x(400 − 2x)
= − 2x2 + 400x
The area is a parabola opens downward, so the maximum area occurs at the parabola vertex.
At the vertex
x = −b/2a
= −400/[2(−2)]
= 100
y = 400 −2x
= 200
So the dimensions of the rectangular field that maximize the enclosed area is 100 ft x 200 ft.
James L.
Thank you so much!!!!02/21/20