Find two consecutive integers such that three more than three times the first exceedstwice the second by 82

Question

Consecutive integers

 

Answer 1

First: x

second is x+1

 

Three more than three times the first                  exceeds twice the second by 82

3x+3                                                      =                 2( x+1)+82

 

3x + 3 = 2(x+1)+82

 

3x + 3 = 2x + 2 + 82

 

3x +3 = 2x + 84

 

3x + 3 - 2x - 84 = 0

 

x - 81 = 0

 

x = 81

 

81 and 82

 

CHECK:

 

  left side: 3(81)+3 = 243 +3 = 246

        vs

 right side: 2(82)+82 = 164 + 82 = 246

 

81 and 82

 

checked, verified, proven, sign, sealed, and delivered.