Arturo O. answered 10/22/17
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pH = 4.0 < 7 ⇒ acidic
pH = -log[H3O+]
[H3O+] = 10-pH = 10-4.0 = 1.0 x 10-4 = 10 x 10-5
Pure water is neutral ⇒ pH = 7
[H3O+] = 10-7 = 1 x 10-7