Sharon Z.
asked • 10/19/17
perimeter is 50, if width were doubled and length were increased by 19 perimeter would be 108m. what is the length and width
Carol H.
answered • 10/19/17
Experienced Mathematics Tutor w/ Master's Degree in Math
Let w = the width
let l = the length
P = 2l + 2w = 50
108 = 2(l + 19) + 2(2w)
108 = 2l + 38 + 4w
70 = 2l + 4w
-50 =-2l - 2w
20 = 2w
w = 10 meters
2l + 2(10) = 50
2l + 20 = 50
2l = 30
l = 15 meters
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