In an examination..

Question

In an examination, a student secures 48% of maximum marks which is 24 marks more than the pass mark. Another student secures only 36% marks which 12 marks is less than the pass mark. Find the pass mark in the examination.

Answer 1

Let M = the maximum and P = the pass mark, then

P + 24 = 0.48 M         (1)

P − 12 = 0.36 M         (2)

 

Dividing (1) by (2) to eliminate M yields

 

(P + 24)/(P − 12) = 4/3

 

4(P − 12) = 3(P + 24)

 

So the pass mark, P, in the examination is 120.